Stopwatch SprinterStoryspinners · word problems

Races with a stopwatch and an odometer: distance is rate times time.

Distance, Rate and Time

Distance is rate times time. In MathBound, the free Algebra I adventure game, Stopwatch Sprinter asks these problems, and the only way past is to solve them.

Part of Solving Linear Equations: chapter 2 of the standard course.

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10 questions, no sign-up, nothing saved. Climbs from the basics to harder questions.

What you will practice

Basic Motion. Solve for distance,rate,or time given the other two variables.
Opposite Directions. Solve motion problems where two objects travel in opposite directions.
Catch-up Motion. Solve motion problems where one object catches up to another (same distance).
Current/Wind. Solve motion problems involving speed of a boat in a current or plane in wind.

Worked examples

Made by the game’s own question engine. Try each one, then open its steps.

Example 1 · Basic Motion

A

cyclist

rides

210

miles

in

3

hours .

What

is

her

average

speed?

$0.014$ $mph$
$70$ $mph$
$207$ $mph$
$630$ $mph$

Show the worked steps

$d = r t,$ $so$ $r = \frac{d}{t} .$
$r = \frac{210}{3} = 70$ $mph.$

Answer: $70$ $mph$

Example 2 · Opposite Directions

Two

towns

are

240

miles

apart.

Two

cars

leave

them

at

the

same

time

and

drive

toward

each

other

at

30

mph

and

30

mph.

In

how

many

hours

do

they

meet?

$4$ $hours$
$2$ $hours$
$8$ $hours$
$5$ $hours$

Show the worked steps

$Driving$ $toward$ $each$ $other,$ $the$ $gap$ $closes$ $at$ $30 + 30 = 60$ $mph.$
$\frac{240}{60} = 4$ $hours .$

Answer: $4$ $hours$

Example 3 · Catch-up Motion

A

cyclist

leaves

at

10:00

AM

at

12

mph.

A

car

leaves

the

same

place

6

hours

later

at

48

mph,

following

the

same

road.

How

far

from

the

start

does

the

car

catch

the

cyclist?

$96$ $miles$
$72$ $miles$
$24$ $miles$
$384$ $miles$

Show the worked steps

$When$ $the$ $car$ $sets$ $off$ $the$ $cyclist$ $is$ $72$ $miles$ $ahead.$
$The$ $car$ $closes$ $the$ $gap$ $at$ $48 - 12 = 36$ $mph.$
$\frac{72}{36} = 2$ $hours .$
$In$ $2$ $hours$ $the$ $car$ $goes$ $48 \cdot 2 = 96$ $miles .$

Answer: $96$ $miles$

Where it is in your textbook

Textbook	Lessons
Standard course	2.7
CPM Core Connections Algebra	2.2.1
Eureka Math Algebra I (EngageNY)	1.25-1.28
Glencoe Algebra 1	2-9, 11-8
Holt McDougal Larson Algebra 1	1.5
OpenStax Elementary Algebra 2e	2.6, 3.5, 8.8
Pearson Algebra 1 Common Core	11-5

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